197k views
3 votes
Find a number that has 4 identical even factors each factor must be greater than one and can have only one and itself as factors

User Margareth
by
7.6k points

2 Answers

4 votes
A number that has only 1 and itself as factors is called a prime number. The only even number (a number divisible by 2) that is also a prime number is 2. So a number that has 2 as its factor 4 times is 8 :)
User Michael Richards
by
8.1k points
1 vote

Answer:

The Number is 16.

Explanation:

Given: Number has 4 Factors.

All 4 factors are same and even.

Factor are greater than 12.

Factors can only has 2 factors that is 1 and itself or we can say factors are prime no.

We need to find this number.

We know that there is only 1 number which is even prime.

So, our required factor is 2.

And required Number = 2 × 2 × 2 × 2 = 16

Therefore, The Number is 16.

User Clattenburg Cake
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.