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I am not good at understanding how to graph this..

I am not good at understanding how to graph this..-example-1
User Ilia  Grabko
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1 Answer

22 votes
22 votes

We are given the following inequality:


y\le(1)/(3)x-6

To graph this inequality we need to graph first the curve that is the border of the solution set of the inequality. This curve is determined when we use an equal sign instead of the inequality sign:


y=(1)/(3)x-6

In this case, the border is a line since it follows the form:


y=mx+b

Where "m" is the slope and "b" is the y-intercept. To graph this line we need two points. The first point is the y-intercept since this is the point where the line touches the y-axis.


(-6,0)

The second point can be determined by setting "y =0" and solving for "x";


0=(1)/(3)x-6

Now we add 6 to both sides:


6=(1)/(3)x

Now we multiply both sides by 3:


18=x

Therefore, the second point is:


(18,0)

Now we graph the line. Going back to the inequality we have that after "y" the inequality sign is "less or equal than", the solutions are the points under the borderline and include the points on the line. Therefore, the graph looks like this:

I am not good at understanding how to graph this..-example-1
User Harri
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2.6k points