Answer:
a) the required time interval is 0.25 s
b) the distance traveled while accelerating is 0.075 m
Step-by-step explanation:
Given that;
Initial speed of the squid u = 0.15 m/s
final speed of the squid v = 0.45 m/s
acceleration a = 1.2 m/s²
Time period T = ?
using equation of motion
v = u + at
solve for t
at = v - u
t = v - u / a
we substitute
t = ( 0.45 - 0.15 ) / 1.2
t = 0.3 / 1.2
t = 0.25 s
Therefore, the required time interval is 0.25 s
b)
the other possible question is; Determine the distance the squid has traveled while accelerating.
using the following expression
v² = u² + 2as
we solve for distance s
2as = v²- u²
s = v²- u² / 2a
we substitute
s = ((0.45)²- 0.15)²) / 2×1.2
s = (0.2025 - 0.0225) / 2.4
s = 0.18 / 2.4
s = 0.075 m
Therefore, the distance traveled while accelerating is 0.075 m