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A mass is hung from a vertical spring and allowed to come to rest or its equilibrium position. The mass is then pulled down an additional 0.25 meters and released. As the mass oscillates it completes one full cycle in 3.0 seconds. Place the numbers below to correctly identify the mass's amplitude, full range of vertical motion, frequency, and period. The full range of vertical motion is the distance between the maximum and minimum heights of the mass.

e amplitude of the spring is______ m.
The full range of vertical motion is _____m.
The frequency of the spring is______ Hz.
The period of the spring is_______ s.

1 Answer

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Answer:

Step-by-step explanation:

Time period of oscillation T = 3 s .

Frequency of oscillation = 1 / T = 1 / 3 = .333 per second .

The mass is pulled down an additional 0.25 meters so amplitude of oscillation A = .25 m .

Full range of vertical motion = .25 x 2 = 0.5 m .

The period of the spring = 3 s .

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