Simplify the expression

Question

asked Nov 12, 2017 146k views

2 Answers

Daniel Falbel · Answer 1 · 2017-11-13T14:01:15+0000

Answer:

$3x^{(1)/(2)}y^(-1)$

Explanation:

The given expression is:

$\frac{15xy}{5x^{(1)/(2)}y^2}$

We have to simplify the above given expression.Thus,

Firstly, divide the constant terms, we get

(15)/(5)=3

Now, applying the exponent law, that is
(x^a)/(x^b)=x^(a-b) , we have

$\frac{xy}{x^{(1)/(2)}y^2}=x^{1-(1)/(2)}y^(1-2)=x^{(1)/(2)}y^(-1)$

Thus, the simplified form of the above given equation is:

$3x^{(1)/(2)}y^(-1)$

Pavel Prochazka · Answer 2 · 2017-11-17T03:59:10+0000

Answer:

The simplified form of given expression
$\frac{15xy}{5x^{(1)/(2)}y^2}$ is
$\frac{3x^{(1)/(2)}}{y}$

Explanation:

Given: Expression
$\frac{15xy}{5x^{(1)/(2)}y^2}$

We have to write the given expression in simplified form,

Consider the given expression
$\frac{15xy}{5x^{(1)/(2)}y^2}$

Divide the numbers
(15)/(5)=3

we get,

$=\frac{3xy}{y^2x^{(1)/(2)}}$

Apply exponent rule ,
$(x^a)/(x^b)\:=\:x^(a-b)$

$\frac{x}{x^{(1)/(2)}}=x^{1-(1)/(2)}=x^{(1)/(2)}$

we get,

$=\frac{3yx^{(1)/(2)}}{y^2}$

Cancel y term, we have,

$=\frac{3x^{(1)/(2)}}{y}$

Thus, The simplified form of given expression
$\frac{15xy}{5x^{(1)/(2)}y^2}$ is
$\frac{3x^{(1)/(2)}}{y}$