Question

Find the values of (x) for which the ball's height is

27
feet.
height (h)= 7+37x-16x^2

Answer 1

sett is to 27
27=7+37x-16x^2
multiply -1 both sides
-27=-7-37x+16x^2
add 27 both sides
16x^2-37x+20=0
use quadratic equation
if yo have
ax^2+bx+c=0
x=
`\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}`

1=16
b=-37
c=20

x=
`\frac{-(-37)+/- \sqrt{(-37)^(2)-4(16)(20)} }{2(16)}`
x=
`(37+/- √(1369-1280) )/(32)`
x=
`(37+/- √(89) )/(32)`
aprox
x=0.861438 or 1.45106