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Andy is waiting at the signal. As soon as the light turns green, he accelerates his car at a uniform rate of 8.00 meters/second2. What is the displacement of Andy’s car after 30.0 seconds?

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-- Accelerating at the rate of 8 m/s², Andy's speed
after 30 seconds is

(8 m/s²) x (30.0 s) = 240 m/s .

-- His average speed during that time is

(1/2) (0 + 240 m/s) = 120 m/s .

-- In 30 sec at an average speed of 120 m/s,
Andy will travel a distance of
(120 m/s) x (30 sec) = 3,600 m

= 3.6 km .

"But how ? ! ?", you ask.

How in the world can Andy leave a stop light and then
cover 3.6 km = 2.24 miles in the next 30 seconds ?

The answer is: His acceleration of 8 m/s², or about 0.82 G
is what does it for him.

At that rate of acceleration ...

-- Andy achieves "Zero to 60 mph" in 3.35 seconds,
and then he keeps accelerating.

-- He hits 100 mph in 5.59 seconds after jumping the light ...
and then he keeps accelerating.

-- He hits 200 mph in 11.2 seconds after jumping the light ...
and then he keeps accelerating.

-- After accelerating at 8 m/s² for 30 seconds, Andy and his
car are moving at 537 miles per hour !
We really don't know whether he keeps accelerating,
but we kind of doubt it.

A couple of observations in conclusion:

-- We can't actually calculate his displacement with the information given.
Displacement is the distance and direction between the starting- and
ending-points, and we're not told whether Andy maintains a straight line
during this tense period, or is all over the road, adding great distance
but not a lot of displacement.

-- It's also likely that sometime during this performance, he is pulled
over to the side by an alert cop in a traffic-control helicopter, and
never actually succeeds in accomplishing the given description.
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