Question

How many mL will a 0.205 mole sample of He occupy at 3.00 atm and 200 K?

Answer 1

`1,122\text{ mL}`

Step-by-step explanation:

Here, we want to get the volume that the gas will occupy

From the ideal gas law, we know that:

`\begin{gathered} PV\text{ = nRT} \\ V\text{ = }(nRT)/(P) \end{gathered}`

where:

n is the number of moles which is 0.205 mole

P is the pressure which is 3 atm

T is the temperature which is 200 K

V is the volume which is what we want to calculate

R is the molar gas constant which is 0.0821 L atm/mol.K

Substituting the values, we have it that:

`V\text{ = }(0.205*0.0821*200)/(3)\text{ = 1.222 L}`

We convert this to mL by multiply the L value by 1000

We have that as:

`1.122\text{ }*\text{ 1000 = 1,122 mL}`