Question

If the vertices of triangle bcd are b(-3,3), c(3,5), and d(-1,0), what is the perimeter

Answer 1

distance formlula
D=
`\sqrt{(x2-x1)^(2)+(y2-y1)^(2)}`

when you want to find the distance between points (x1,y1) and (x2,y2)


we nee
distace from
b to c
c to d
d to b


b to c is (-3,3) to (3,5)
D=
`\sqrt{(3-(-3))^(2)+(5-3)^(2)}`=2√10

c to d is (3,5) to (-1,0)
D=
`\sqrt{(-1-3)^(2)+(0-5)^(2)}`=√41

d to b is (-1,0) to (-3,3)
D=
`\sqrt{(-3-(-1))^(2)+(3-0)^(2)}`=√13

add

b to c+c to d+d to b=2√10+√41+√13

perimiter=2√10+√41+√13 units