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How do I solve for 5t-3/-2=t+3/2

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(5t-3)/(-2)=(t+3)/(2) \\\\ 2(5t-3)=-2(t+3) \\\\ 10t-6=-2t-6 \\\\ 10t+2t=-6+6\\\\ 12t=0 \\\\ \boxed{t=0}
User Tgandrews
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