The answer is 25%.
This is an example of Mendelian monohybrid cross.
If:
A - (dominant) allele for gray fur
a - (recessive) allele for orange fur
Then:
AA - dominant homozygous
Aa - heterozygous
aa - recessive homozygous
The cross between two heterozygous will be:
Parents: Aa x Aa
Offspring: AA Aa Aa aa
Thus, the offspring will be: 1 out of 4 (25%) dominant homozygous (AA), 2 out of 4 (50%) heterozygous (Aa), and 1 out of 4 (25%) recessive homozygous (aa).
Since the recessive condition results in orange fur, only recessive homozygous (aa) will have orange fur, which is 25% of all the offspring.