Question

Calculate the number of molecules in 214 g of calcium hydroxide

Answer 1

1.74 × 10²⁴ molecules are present in 214 g of calcium hydroxide.

Step-by-step explanation

Step 1: Calculate the moles of calcium hydroxide in 214 g using the mole formula.

The molar mass of calcium hydroxide = 74.093 g/mol

`Mole=\frac{Mass}{Molar\text{ }mass}=\frac{214\text{ }g}{74.093\text{ }g\text{/}mol}=2.888262049\text{ }mol`

Step 2: Convert 2.888262049 moles of calcium hydroxide to molecules using Avogadro's constant.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.

∴ 2.888262049 moles of calcium hydroxide is equal to

`\frac{2.888262049\text{ }mol}{1\text{ }mol}*6.022*10^(23)\text{ }molecules=1.74*10^(24)\text{ }molecules`

Hence, 1.74 × 10²⁴ molecules are present in 214 g of calcium hydroxide.