Question

Explain in detail, the process of finding the perimeter and the area of a rectangle with a length of (3x+5) and a width of (2x-2).

Answer 1

Given data:

The length of the rectangle is l=(3x+5) .

The width of the rectangle is b= (2x-2).​

The expression for the perimeter is,

`P=2(l+b)`

Substitute the given values in the above expression.

`\begin{gathered} P=2(3x+5+2x-2) \\ =2(5x+3) \\ =10x+6 \end{gathered}`

The expression for the area is,

`A=l* b`

Substitute the given values in the above expression.

`\begin{gathered} A=(3x+5)(2x-2) \\ =6x^2-6x+10x-10 \\ =6x^2+4x-10 \end{gathered}`

Thus, the perimeter is 10x+6, and the area is 6x^(2) +4x-10.