Question

If 20 atoms of aluminum react with 45 molecules of chlorine gas, which reactant is limiting and how many more atoms/molecules would be required to use up all the reactants?

Answer 1

Al:ch2 an molar ratio.

2:3 and an x. X is 30. 20/2 = 10 so an answer is

45/3 = 15. Both ratios are used

45 - 30 = 15 CL2 left.

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Answer 2

Step-by-step explanation:

`2Al+3Cl_2\rightarrow 2AlCl_3`

According to reaction, 2 atoms of aluminum gas reacts with 3 molecules of chlorine gas.

Then 20 atoms of aluminum will react with :

`(3)/(2)* 20=30 molecules` of chlorine

Aluminum is a limiting reagent.

Molecules of chlorine left unreacted: 45 - 30 molecules = 15 molecules

Then 15 molecules of chlorine gas will react with :

`(2)/(3)* 15=10 atoms` of aluminum

10 more atoms of aluminum will required to use up all chlorine.