Question

The Porsche 911 turbo S is one of the fastest production cars in the world. It can go from 0-60 mph (0-27.7 m/s) in 2.9 seconds. What is the acceleration of this car in m/s^2?

Answer 1

Acceleration = 9.55m/s²

Step-by-step explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 27.7m/s

Time = 2.9 secs

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

`Acceleration (a) = (final \; velocity - initial \; velocity)/(time)`

Substituting into the equation, we have;

`a = (27.7 - 0)/(2.9)`

`a = (27.7)/(2.9)`

Acceleration = 9.55m/s²