Question

The Hubble telescope’s orbit is 5.6 × 105 meters above Earth’s surface. The telescope has a mass of 1.1 × 104 kilograms. Earth exerts a gravitational force of 9.1 × 104 newtons on the telescope. The magnitude of Earth’s gravitational field strength at this location is

Answer 1

Gravitational force = 9.1 x 10⁴ newtons

Mass = 1.1 x 10⁴ kilograms

Gravitational field strength = 9.1 x 10⁴ newtons / 1.1 x 10⁴ kilograms

= ( 9.1 / 1.1) (newton / kilogram)

= 8.3 newton/kg

or 8.3 m/s² .