Question

HELP!!!!!!!PLZZZ!!!!!

Answer 1

Statement:

A skydiver jumps from a plane.

To find out:

The velocity with which he would be travelling after 1 second.

Solution:

• Initial velocity (vi) = 0 m/s [since he was at rest]
• Time (t) = 1 s
• Acceleration due to gravity (g) =
  `10m {s}^( - 2)`
• Let the final velocity be vf.
• We know the equation of motion for a freely falling body, i.e.,

`vf = gt + vi`

• Putting the values in the above equation, we get

`vf = 10(1) + 0 \\ = > vf = 10 \: m {s}^( - 1)`

Answer:

The skydiver will be travelling 10 m/s after 1 second.

Hope you could understand.

If you have any query, feel free to ask.

Answer 2

`\qquad \qquad\huge \underline{\boxed{\sf Answer}}`

Let's solve ~

As the sky diver jumps from the plane it's initial velocity is 0

that is :

• vi = 0

we have to find his speed after 1 second, so

• t = 1

Now, let's plug the values in the formula to find vf ( final velocity )

`\qquad \sf  \dashrightarrow \: vf = 10t + vi`

`\qquad \sf  \dashrightarrow \: vf = 10(1) + 0`

`\qquad \sf  \dashrightarrow \: vf = 10 \: \: m {s}^( - 1)`