210k views
1 vote

CaSO3 (s) → → → → CaO (s) + SO2 (g)

What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.10 atm?



1 Answer

4 votes
Using the ideal gas law, the number of moles SO2 is equal to PV/RT, or pressure times volume divided by the gas constant and temperature. This is 14.5*1.1/((2.5+279.15)*.082), or 0.66 moles. Since one mole CaSO3 is consumed for every mole SO2 generated, 0.66 moles of CaSO3 are consumed. CaSO3 has a molar mass of 40+32+16*3=120 grams, so .66 moles of CaSO3 is equal to 80 grams, our final answer.
User Gjergji
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.