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The function f(x) is graphed below. 4 2 -3 -2 2 a Using interval notation, the domain is: Using interval notation, the range is: = Determine f(3) = Find the number of solutions to f(x) = - 1: The number of y-intercepts is: The number of x-intercepts is: I The number of zeros is: Over the interval [ -2,0), the function is Select an answer v Over the interval [0, 2], the function is Select an answer v Over the interval (2, 3), the function is Select an answer v Over the interval (3,5), the function is Select an answer v The minimum value is: The maximum value is:

The function f(x) is graphed below. 4 2 -3 -2 2 a Using interval notation, the domain-example-1
User Qarl
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The domain of the function is the set of all input x values for which the function is real and defined.

Hence, the domain is [-2, 5].

The range of the function is the set of all output y values of the function.

Hence, the range is [-4, 2].

At x=3, the corresponding y value is 1.

Therefore, f(3)=1.

The corresponding x values when the y value f(x)=-1 are x=-1 and x=5.

Hence, the number of solutions to f(x)=-1 : 2.

y intercept is the point where the graph of the function meets the y axis. The graph meets the y axis only once.

Hence, the number of y intercepts is 1.

y intercept is the point where the graph of the function meets the x axis. The graph meets the x axis three times.

Hence, the number of x intercepts is 3.

The zeroes of a function are the same as the x intercepts.

Hence, the number of zeroes is 3.

Over the interval [-2, 0], the function is increasing.

Over the interval [0, 2], the function is decreasing.

Over the interval [2, 3], the function is increasing.

Over the interval [3, 5], the function is decreasing.

The minimum value is -4.

The maximum value is 2.

User Nguyen Tuan Anh
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