Question

Determine a submarines acceleration if it's initial velocity is 9.0 m/s and it travels 1.54 km in 2 min

Answer 1

`acceleration=(\Delta v)/(\Delta t)\\\\ \Delta t=2min=120s\\\\s=1,54km=1540m\\\\ acceleration=(v_(f)-v_(i))/(\Delta t)\\\\ \Delta v=(s)/(t)\\ v_(f)-v_(i)=(s)/(t)\\ v_(f)=(1540)/(120)+9=21,83(m)/(s)\\\\ accleration=(21,83-9)/(120)=(12,83)/(120)=\boxed{0,107(m)/(s)}`