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Hi I need help please

Hi I need help please-example-1

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Answer/Step-by-step explanation:

Recall: if two figures are similar, we know that the ratio of their areas = the square of the ratio of their corresponding sides

Apply this knowledge to solve the problems given.

✔️Problem 1 (4-sided polygon):

Let the missing area be x cm²

Therefore,


(x)/(9) = (8^2)/(4^2)


(x)/(9) = (64)/(16)


(x)/(9) = 4

Multiply both sides by 9

x = 9*4

x = 36 cm²

✔️Problem 2 (3-sided polygon):

Let the missing area be y cm²

Therefore,


(y)/(240) = (8^2)/(32^2)


(y)/(240) = (64)/(1,024)


(y)/(240) = (1)/(16)

Multiply both sides by 240

y = ¹/16 × 240

y = 15 cm²

✔️Problem 3 (5-sided polygon):

Let the missing area be z cm²

Therefore,


(z)/(40) = (3^2)/(2^2)


(z)/(40) = (9)/(4)

Multiply both sides by 40


z = (9)/(4) * 40


z = (9)/(1) * 10

z = 90 cm²

User Prashant Shilimkar
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