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PLEASE HELP!!!

A reaction is in equilibrium as shown: A + B C + D. Calculate the equilibrium constant if the final concentrations stabilize at:

A = 9.60 M
B = 10.0 M
C = 4.00 M
D = 4.00 M

User MyGGaN
by
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2 Answers

5 votes
Well...
A + B = C + D

(CD) / (AB)

(4) (4) / (9.6) (10)

16 / 96 = 0.167

Hope this helps!
User VerizonW
by
9.2k points
3 votes

Answer : The value of equilibrium constant is, 0.166

Solution : Given,

Concentration of A = 9.60 M

Concentration of B = 10.0 M

Concentration of C = 4.00 M

Concentration of D = 4.00 M

The equilibrium reaction will be,


A+B\rightleftharpoons C+D

The expression for equilibrium constant is,


K_c=([C][D])/([A][B])

Now put all the given values in this expression, we get the values of equilibrium constant.


K_c=((4M)* (4M))/((9.60M)* (10M))=0.166

Therefore, the value of equilibrium constant is, 0.166

User Xcross
by
8.8k points
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