Question

Can anyone help. Greatly appreciate:)

Answer 1

Area= 12 units squared, Perimeter= 16.12899

Explanation:

`AC= \sqrt{(4-0)^(2)+ (0+4)^(2)} = 4√(2)`

`AB= \sqrt{(0-4)^(2)+ (2-0)^(2) } = 2√(5)`

`BC= \sqrt{(0-0)^(2)+ (2+4)^(2) }= 6`

So, perimeter=
`4√(2) + 2√(5) +6= 16.12899`

`Area= (1)/(2)bh\\`

`= (1)/(2)BC\sqrt{(4-0)^(2)+(0-0)^(2) }`

`= 12`
`units^(2)`