Answer:
x=3
Explanation:
The approach is not very different from regular fractions.
You have to get to a common denominator to be able to add them.
10 is a good denominator (multiply the denominators).
multiply the first term by 5, and the second one by 2:
![(5 \cdot (x+1))/(5 \cdot 2) + (2 \cdot (x+2))/(2 \cdot 5) = 3](https://img.qammunity.org/2022/formulas/mathematics/high-school/wayu8etoztrwpzqyww0o6drj18h3uhftir.png)
![(5x+5 + 2x+4)/(10) = 3](https://img.qammunity.org/2022/formulas/mathematics/high-school/crgrannoiscepqt9qb5reyy9xr68edvrqi.png)
![(7x+9)/(10) = 3](https://img.qammunity.org/2022/formulas/mathematics/high-school/89n5k0fbav57rpws2gkqheliwmqlhwh1rr.png)
7x + 9 = 30
7x = 30 - 9
x = 3
let me know if you need more details on one of the steps