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I need help I don’t know how to linear functions containing two points

User Mark Horgan
by
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1 Answer

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10 votes

The linear function that the any variables have the highest degree of 1

A linear function have two, three five.. infinity number of variables.

for eg :


\begin{gathered} 1.4x+7u=7x+3y\text{ is a linear function beacuse the degr}ee\text{ of each variable is 1} \\ 2.7x^2+8y+6c-u=0\text{ is not a linear function beacuse the degr}e\text{ of the variable x is 2} \\ \text{ which is greater than 1} \end{gathered}

The expression for the linear function is :


(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)

Here we have y = f(x)

5) f(-2)= -3 & f(0)=5

Here, we have x =-2, and y=-3

x=0 and y =5

So, the equation


\begin{gathered} (y-(-3)_{})=\frac{5_{}-(-3)}{0-(-2)_{}}(x-(-2)_{}) \\ y+3=(5+3)/(2)(x+2) \\ y+3=(8)/(2)(x+2) \\ y+3=4(x+2) \\ y+3=4x+8 \\ y=4x+8-3 \\ y=4x+5 \end{gathered}

Answer : Required equation : y = 4x+5

6) f(-2)=4 & f(-5)=7

Here we have at x =-2 and f(-2)=4 i.e y = 4

and at x = -5 and f(-5) =7i.e y =7

So, the equation is :


\begin{gathered} (y-4_{})=\frac{7_{}-4}{-5_{}-(-2)}(x-(-2)) \\ y-4=(3)/(-3)(x+2) \\ y-4=(-1)(x+2) \\ y-4=-x-2 \\ x+y=4-2 \\ x+y=2 \end{gathered}

Answer : Required Equation : x + y =2

User Satomi
by
2.6k points
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