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I just need the answer you dont have to deeply explainA. 4 to the square root of 2B. 3 to the square root of 2C. 2 to the square root of 2 D 8

I just need the answer you dont have to deeply explainA. 4 to the square root of 2B-example-1
User Imran Rana
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1 Answer

17 votes
17 votes

Given:

Hypotenuse=x, Adjacent side=4, and angle is 45 degrees.

Consider the cos formula.


\cos \theta=\frac{\text{Adjacent side}}{\text{hypotenuse}}
\text{ Substitute hypotenuse= x, adjacent side =4, and }\theta=45^o,\text{ we get}
\cos 45^o=(4)/(x)

Using the cross-product method, we get


x=(4)/(\cos 45^o)
\text{Use }\cos 45^o=\frac{1}{\sqrt[]{2}}


x=\frac{4}{\frac{1}{\sqrt[]{2}}}=4*\frac{\sqrt[]{2}}{1}=4\sqrt[]{2}

The length of x is


4\sqrt[]{2}

Option A is correct.

User Stathis Andronikos
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2.9k points