Question

What is the temperature of 0.80 mol of a gas stored in a 275 mL cylinder at 175 kPa?

Answer 1

P*V=n*R*T (Pressure*Volume = mol * 0,082 (constant)* temperature )
175 kPa = 1,727 atm
V=275 ml = 0.275 liters
T=(P*V)/(n*R)=1,727*0.275/0.8*0.082=7,23 Kelvin.

Answer 2

7.23 K

Solution:

Data Given:

Moles = n = 0.80 mol

Temperature = T = ??

Pressure = P = 175 kPa = 1.727 atm

Volume = V = 275 mL = 0.275 L

Formula Used:

Let's assume that the gas is acting as an Ideal gas, then according to Ideal Gas Equation,

P V = n R T

where; R = Universal Gas Constant = 0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for T,

T = P V / n R

Putting Values,

T = (1.727 atm × 0.275 L) ÷ (0.80 mol × 0.082057 atm.L.mol⁻¹.K⁻¹)

T = 7.23 K