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4 votes
Solve the system of equations 3r – 4s = 0 and 2r + 5s = 23

2 Answers

4 votes

Answer:

The answer would be (8, -7)

User Hosseio
by
7.9k points
2 votes

3r-4s=0

3r=4s

r=(4)/(3)s


2r+5s=23

2((4)/(3)s)+5s=23

(8)/(3)s+5s=23

5(8)/(3)s=23

s=3


3r-4s=0

3r-4(3)=0

3r=12

r=4

s=3, r=4

Check:

2r+5s=23

2(4)+5(3)=23

8+15=23

23=23 CHECK
User Trey Bean
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7.2k points