Question

X^2+14x-15=0 solve by completing square
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Answer 1

`{x}^(2) + 14x - 15 = 0 \\ {x}^(2) - x + 15x -15 = 0 \\ x(x - 1) + 15(x - 1) = 0 \\ (x - 1)(x + 15) = 0 \\ \boxed{x = 1} \\ \boxed{x = - 15}`

x=1 and x=-15 is the right answer.