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Find the height of a baseball with a mass of 0.15 kg that has a GPE of 73.5 J.

Help please?

User Gokul E
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2 Answers

5 votes
Hight is 50 b/c it is on the ledt side



User Hernaldo
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Gravitational Potential Energy of an object, relative to the ground =

(mass) x (acceleration of gravity) x (height above the ground)


73.5 J = (0.15 kg) x (9.8 m/s²) x (height above the ground).

1 J = 1 kg · m² / s²

73.5 kg·m²/s² = (0.15 kg) · (9.8 m/s²) · (height)

Divide each side by (0.15 kg):

(73.5 kg·m² / (0.15 kg·s²) = (9.8 m/s²) · (height)

Divide each side by (9.8 m/s²):

(73.5 kg·m²·s²) / (0.15 kg·s² · 9.8 m) = (height)

After doing all the arithmetic on the left side:

(73.5) / (0.15 · 9.8) (m) = height

50 (m) = height
User Mega
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