Question

a bag contains 5 red skittles, 3 purple skittles, and 2 orange skittles.A skittle is removed and not replaced, then another skittles.A is removed.what is the probability that is a red skittle then a orange skittle?

Answer 1

The probability of two independant events
`P_a` and
`P_b` can be found by multiplying the individual probabilities like so:

`P_t=P_(a)*P_b`

For each individual probability we can find the answer via a simplfied representation:

`P_x = (wanted)/(total)`

For the first skittle (red) we have:

`P_(red) = (red)/(total)=(5)/(10)=0.5`

For the second skittle (orange) we have:

`P_(orange) = (2)/(9) = 0.2222...`
**(Notice that the total is now NINE since we didn't put the first red one back in the bag.)

So:

`P_(total) = P_(red) * P_(orange)`

`P_(total) = (5)/(10) * (2)/(9)`

`P_(total) = (10)/(90)=(1)/(9) \approx 0.1111 \approx 11.11\%`