Question

Solve using ARE= LENGTH X WIDTH.

a rectangle is twice as long as it is wide. If both its dimensions are increased by 4 m, its are is increased by 88m^2. Find the dimensions of the original rectangle.

Answer 1

x=lebgth
y=width.
I suggest this system of equations:
x=2y
(x+4)(y+4) - xy=88

we can solve this system by substitution method.
(2y+4)(y+4)-2y(y)=88
2y²+8y+4y+16-2y²=88
12y=88-16
12y=72
y=72/12
y=6

x=2y
x=2(6)=12

Answer: the dimensions of the original rectangle are:
length=12 m
width=6 m