Question

50POINTS!

Using the ideal gas law (PV=nRT) solve for the missing. Variable. R= 0.08206atm*L/mol*k

If 22.9L of an ideal gas was collected at STP. How many moles of the gas were present?

A. 1.02 moles
B. 5.99 moles
C. 3.05 moles
D. 2.74 moles

Answer 1

A. 1.02 moles .

Step-by-step explanation:

Hello!

In this case, given the ideal gas equation, as we need to solve for moles, we divide both sides by RT to get:

`n=(PV)/(RT)`

Thus, by plugging in the pressure and temperature at STP (1.00 atm and 273.15 K respectively) we obtain:

`n=(1.00atm*22.9L)/(0.08206(atm*L)/(mol*K)*273.15K)\\\\n=1.02mol`

Therefore, the correct answer is A. 1.02 moles

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