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Quadratic formula to find the values of x that are solutions to the equation 2x2 + 3x + 1 = 0

User Agradl
by
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1 Answer

9 votes

Answer:

x = -0.5 or -1

Explanation:

Given the quadratic equation;

2x² + 3x + 1 = 0

The standard form of a quadratic equation is ax² + bx + c = 0

Therefore, a = 2, b = 3 and c = 1

Quadratic equation formula is;


x = \frac {-b \; \pm \sqrt {b^(2) - 4ac}}{2a}

Substituting into the equation, we have;


x = \frac {-3 \; \pm \sqrt {3^(2) - 4*2*1}}{2*2}


x = \frac {-3 \pm \sqrt {9 - 8}}{4}


x = \frac {-3 \pm \sqrt {1}}{4}

Simplifying further, we have;


x = \frac {-3 \pm 1}{4}


x_(1) = \frac {-3 + 1}{4}


x_(1) = \frac {-2}{4}


x_(1) = -0.5

To find the value of x2;


x_(2) = \frac {-3 - 1}{4} \\x_(2) = \frac {-4}{4} \\x_(2) = -1

Therefore, the value of x = -0.5 or -1

User Billy ONeal
by
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