A 12.8 mm 110°C find the area of the sector formed

Kid Diamond asked Sep 12, 2023

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Kid Diamond asked Sep 12, 2023

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12 votes

Since 110 degress is equal to 11pi/18 then the area is

$(12.8)^2((11\pi)/(18))((1)/(2))=(81.92)((11\pi)/(18))=157.275mm^2$

Mazatsushi answered Sep 17, 2023

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