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What is the mole ratio of oxygen to propane (C3H8) in the following equation?C3H8 + 5O2 ➡ 3CO2 + 4H2O 5:1 10:11 10:3 1:10
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What is the mole ratio of oxygen to propane (C3H8) in the following equation?C3H8 + 5O2 ➡ 3CO2 + 4H2O

5:1

10:11

10:3

1:10

User William Symionow
by
8.2k points

1 Answer

4 votes
That would be 5 : 1

since there are 5 moles of oxygen needed to burn 1 mole of propane to burn (completely) to give CO2 and H2O
User Vinodkone
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8.5k points
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