Find two consecutive integers such that the sum of twice the larger number and three times the smaller number is 242?

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asked Dec 15, 2017 53.6k views

1 Answer

Shams Reza · Answer 1 · 2017-12-22T02:25:04+0000

let x be the smaller number and y be the larger one
so x + 1 = y
242 = 2y + 3x
use substitution to solve for one of the variables
242 = 2(x + 1) + 3x
242 = 2x + 2 + 3x
240 = 5x
48 = x

the numbers are 48 and 49

Find two consecutive integers such that the sum of twice the larger number and three times the smaller number is 242?

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