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Find two consecutive integers such that the sum of twice the larger number and three times the smaller number is 242?
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Find two consecutive integers such that the sum of twice the larger number and three times the smaller number is 242?

User Teemu Kurppa
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1 Answer

4 votes
let x be the smaller number and y be the larger one
so x + 1 = y
242 = 2y + 3x
use substitution to solve for one of the variables
242 = 2(x + 1) + 3x
242 = 2x + 2 + 3x
240 = 5x
48 = x

the numbers are 48 and 49
User Shams Reza
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8.3k points
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