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calculate the molality of a solution that has 18.0g of glucose, C6H12O6, dissolved in 80.0g of water.

calculate the molality of a solution that has 18.0g of glucose, C6H12O6, dissolved-example-1
User Mayuko
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1 Answer

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13 votes

Answer

1.25M

Step-by-step explanation

to calculate the molality we use the following equation

Molality = moles of solute / Kg of solvent

step 1: to find the moles of glucose we divide the mass by the Molar mass of glucose

moles = mass (g)/ Molar mass (g/mol)

= 18.0 g / 180,156 g/mol

= 0.0999 moles of glucose

now that we have moles of glucose, the next step is to convert 80.0g of water to Kg of water

1 kg = 1000g

Kg of water = 80g/1000g /kg

= 0.08Kg

Molality = 0.0999 mols / 0.08 kg

= 1.25M

User Dave Cluderay
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