Question

Find a number that has 4 identical even factors each factor must be greater than one and can have only one and itself as factors

Answer 1

3, 1, 9, 0.

these are just a few numbers I know, but im not very sure if they are correct because I don't quite understand this question.

Answer 2

The Number is 16.

Explanation:

We are given,

Required number has 4 identical even factros.

Factors are greater than 1 and

Factor is prime number. Since it has onle 2 factor 1 and itself.

To find: Number satisfying above conditions.

We only have 2 as even prime number.

So, Required Number = 2 × 2 × 2 × 2 = 16

Therefore, The Number is 16.