108k views
2 votes
Dree rolls a strike in 6 out of 10 frames of bowling. What is the experimental probability that Dree will roll a strike in the first frame of the next game? Explain why a number cube would not be a good way to simulate this situation

User Vuryss
by
8.1k points

2 Answers

4 votes

Answer: Experimental probability will be


(3)/(5)

Explanation:

Since we have given that

Number of frames of bowling = 10

Number of rolls a strike = 6

So, Experimental probability is given by


\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}=(6)/(10)=(3)/(5)

As we know that the number of outcomes in a cube is 6 but we want total number of outcomes which should be 10.

So, Number cube would not be a good way to simulate this situation.

Hence, Experimental probability will be


(3)/(5)


User Dexter Legaspi
by
8.6k points
3 votes
The correct answer for the question that is being presented above is this one: the experimental probability that Dree will roll a strike in the first frame of the next game

prob = 6/10 = 3/5

a cube has 6 sides, so division by 6 would be the model for probs, we need a division by 5 or 10 or 15 ,etc

User Haseeb
by
7.9k points