Question

How do I solve for 5(+20)=7+30?

Answer 1

First, we apply the distributive property of multiplication:

`\begin{gathered} 5x+5\cdot20=7x+30, \\ 5x+100=7x+30. \end{gathered}`

Subtracting 5x from the above equation we get:

`\begin{gathered} 5x+100-5x=7x+30-5x, \\ 100=2x+30. \end{gathered}`

Now, subtracting 30 we get:

`\begin{gathered} 100-30=2x+30-30, \\ 70=2x\text{.} \end{gathered}`

Finally, dividing by 2 we get:

`\begin{gathered} (2x)/(2)=(70)/(2), \\ x=35. \end{gathered}`

Answer: x=35.