Answer:
0.46 m
Step-by-step explanation:
By Hooke's law, the applied force on the spring is equal to the spring constant times the change in length.
F = kx
Since a 1.6 kg mass hangs from the spring, the force applied is the weight of this mass, so
F = mg
F = (1.6 kg)(9.8 m/s²)
F = 15.68 N
Then, we can solve the initial equation for x and replace the values
x = F/k
x = 15.68/34
x =0.46 m
Therefore, the spring is stretched 0.46 m