Question

What is the solution for the following equation?
x^2-6x+9=11

Answer 1

make one side equal zero
minus 11 to both sides
x^2-6x-2=0
another quadratic equation

if you hahve
ax^2+bx+c=0
x=
`\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}`

1x^2-6x-2=0
a=1
b=-6
c=-2

x=
`\frac{-(-6)+/- \sqrt{(-6)^(2)-4(1)(-2)} }{2(1)}`
x=
`(6+/- √(36+8) )/(2)`
x=
`(6+/- √(44) )/(2)`
x=
`(6+/- 2√(11) )/(2)`
x=
`3+/- √(11)`
x=
`3+ √(11)` or
`3- √(11)`

aprox
x=6.31662 or -0.316625