Question

Which is the solution to the following equation?
4x^2-12x+9=5

Answer 1

we assume that
if xy=0
x and y=0

first make it equal to zero

minus 5 on both sides
4x^2-12x+4=0
undistribute 4 for ease
4(x^2-3x+1)=0
since 4 does not equal zero, and the only thing that will get it to zero is 0,
x^2-3x+1=0
use quadratic equation

if you hahve
ax^2+bx+c=0
x=
`\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}`
1x^2-3x+1=0
a=1
b=-3
c=1

x=
`\frac{-(-3)+/- \sqrt{(-3)^(2)-4(1)(1)} }{2(1)}`
x=
`(3+/- √(9-4) )/(2)`
x=
`(3+/- √(5) )/(2)`
x=
`(3+ √(5) )/(2)` or
`(3- √(5) )/(2)`


aprox
x=2.61803 or 0.381966