Question

The pressure of a sample of gas at 10.00C increases from 700. mm Hg to 900. mm Hg. What is the new temperature?

Answer 1

Gay Lussac's Law :

When the volume is constant, the gas pressure is proportional to its absolute temperature

`\tt (P_1)/(T_1)=(P_2)/(T_2)`

Input the value:

`\tt (700\:mmHg)/(283\:K)=(900\:mmHg)/(T_2)\\\\T_2=(900* 283)/(700)=363.86\:K=90.86^oC`