Question

compute the value of the discriminant and give the number of real solutions of the quadratic equation. -3x^2+x-1=0

Answer 1

the discriminant is the bit under the squaer root sign in the quadratic formula

when you have
ax^2+bx+c=0
the discriminant is
`b^(2)-4ac`
if
discriminant>0 then have 2 real solutions/roots
discriminant=0 then have 1 real solution/root
discriminat<0 then have no real roots (2 imaginary roots)


-3x^2+x-1=0
a=-3
b=1
c=-1


`1^(2)-4(-3)(-1)`=1-12=-11
-11<0
has zero real solutions