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What mass in grams would 5.7L of hydrogen gas occupy at STP?​

User Richytong
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1 Answer

6 votes

Answer: The correct answer is: " 0.54 g " .

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Step-by-step explanation:

Note that "hydrogen gas" is:

H₂ (g) ; that is: a "diatomic element" (diatomic gas) ;

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The molecular weight of "H" is: 1.00794 g ;

(From the Periodic Table of Elements).

So, the molecular weight of: H₂ (g) is:

" 1.00794 g * 2 = 2.01588 g ; {use calculator) ;

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Note the conversion for a gas at STP:

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1 mol of a gas = 22.4 L gas;

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i.e. " 1 mol / 22.4 L " ;

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So: " 5.7 L H₂ (g)
* (1 mol H_(2) )/(22.4 L) *(2.01588 g)/(mol) =? ;

The "L" ("literes" cancel out to "1" ; since "L/L = 1 ;

The "mol" (moles) cancel out to "1" ; since "mol/mol = 1 ;

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and we are left with:

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[5.7 * 2.104588 g ] / 22.4 = ? g ;

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→ [ 11.9961516 g ] / 22.4 =

0.53554248214 g ;l

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We round this value to: " 0.54 g " ;

→ since "5.7 L " has 2 (two) significant figures;

22.4 is an exact number conversion;

and "5.7 L" has fewer significant figures than:

" 2.104588 " ; or: " 1.00794 " .

→ as such: We round to "2 (two) significant figures."

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Hope this is helpful. Wishing you the best in your academic endeavors!

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User Syed Rafay
by
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