Question

How do i solve 4m^2+3m-1=0 using the quadratic formula

Answer 1

quadratic formulat is used when a^2+bx+c=0 x=
`\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}` 4m^2+3m-1=0 a=4 b=3 c=-1 input x=
`\frac{-3+/- \sqrt{3^(2)-4(4)(-1)} }{2(4)}` x=
`(-3+/- √(9+16) )/(8)` x=
`(-3+/- √(25) )/(8)` x=
`(-3+/-5 )/(8)` x=
`(-8)/(8)` or
`(2)/(8)` x=-1 or 1/4