Find the measure of a supplement of a 20 3/4 degrees

asked Jan 20, 2015 193k views

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5 votes

$supplement = 20 \ 3/4 + x =180 \\20 \ 3/4 + x =180 \\x = 180 - 20 \ 3/4 \\\boxed{x = 159.25}$

Sqoshu answered Jan 23, 2015

7.0k points

2 votes

$20 (3)/(4)= (83)/(4) \\ \\ 180^((4)-(83)/(4)= (720-83)/(4)=\boxed{(637)/(4)=159 (1)/(4)-the \ suplement}$

Lack answered Jan 26, 2015

by Lack

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