The area of circle A is nine times the area of circle B.
c1:
c=2*pi*r
so imagining r = 3 then, c=6pi
area=pi*r^2 => 9pi
c2:
so imagining r = 9 then, c=18pi
area=pi*r^2 => 81pi
81/9 = 9 so the answer is:
The area of circle A is nine times the area of circle B.